# GMAT - Graduate Management Admission Test Quantitative Questions

Home > GMAT > Gmat Test Quantitative Section

Last year for every 100 million vehicles that travelled on a certain highway, 96 vehicles were involved in accidents. If 3 billion vehicles traveled on the highway last year, hom many of those vehicles were involved in accidents (1 billion=1,000,000,000)?

### Answer & Explanation:

Answer: Option C

Explanation:

According to the information given 96 out of every 100 million vehicles were involved in an accident which gives us the ration 96/100,000,000. Thus all we have to do is multiply this ratio with the new amount of 3,000,000,000 to get the new accident figure.

(96/100,000,000)x3,000,000,000=2880

In the formula V=1/(2r)^3, if r is halved, then V is multiplied by?

### Answer & Explanation:

Answer: Option B

Explanation:

If r is halved then it is possible to substitute 1/2r for r in the formula and simplify:

1/(2(1/2r))^3=1/(8(1/8r^3))=1/r^3

Compared to the original where:

V=1/(2r)^3=1/(8r^3), the new value of V is 1/r^3 or

8(1/(8r^3))=8V

When r is halved then V is multiplied by 8.

A television manufacturer produces 600 units of a certain model each month at a cost to the manufacturer of �90 per unit and all of the produced units are sold each month. What is the minimum selling price per unit that will ensure that the monthly profit (revenue from sales minus production costs) on the sales of these units will be at least �42,000?

### Answer & Explanation:

Answer: Option D

Explanation:

Let's say x is the amount that the manufacturer sells each unit for, then the profit per unit can be expressed as x-90. We also know that 600 units have been produced and that the total profit has to be at least �42,000.

600(x-90)≥42,000

x-90≥70

x≥160

What is the 25th digit to the right of the decimal point in the decimal form of 6/11?

### Answer & Explanation:

Answer: Option C

Explanation:

The fraction in the decimal form is:

6/11=0.545454...Every odd-numbered digit to the right of the decimal point is 5 so the 25th digit must then be 5.

A club collected exactly �599 from its members. If each member contributed at least �12, what is the greatest number of members the clun could have?

### Answer & Explanation:

Answer: Option C

Explanation:

To determine the greatest possible number of members, first recognize that each member had to contribute the lowest amount given. Build an inequality for the individual contributions and the total amount collected, with n=the number of members in the club, and solve for n.

12n≤599

n≤49 11/12

Since n represents individual people it must be a whole number. Thus the greatest number of people is 49.