# Line Charts Questions and Answers

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**Study the following line graph and answer the questions.
**

Exports from Three Companies Over the Years (in Pesetas)

For which of the following pairs of years the total exports from the three Companies together are equal?

### Answer & Explanation:

Answer: Option D

Explanation:

Total exports of the three Companies X, Y and Z together, during various years are:

In 1993 = (30 + 80 + 60) = 170

In 1994 = (60 + 40 + 90) = 190

In 1995 = (40 + 60 + 120) = 220

In 1996 = (70 + 60 + 90) = 220

In 1997 = (100 + 80 + 60) = 240

In 1998 = (50 + 100 + 80) = 230

In 1999 = (120 + 140 + 100) = 360

Clearly, the total exports of the three Companies X, Y and Z together are same during the years 1995 and 1996.

Average annual exports during the given period for Company Y is approximately what percent of the average annual exports for Company Z?

### Answer & Explanation:

Answer: Option D

Explanation:

Analysis of the graph: From the graph it is clear that

1. The amount of exports of Company X (in Pesetas) in the years 1993, 1994, 1995, 1996, 1997, 1998 and 1999 are 30, 60, 40, 70, 100, 50 and 120 respectively.

2. The amount of exports of Company Y (in Pesetas.) in the years 1993, 1994, 1995, 1996, 1997, 1998 and 1999 are 80, 40, 60, 60, 80, 100 and 140 respectively.

3. The amount of exports of Company Z (in Pesetas) in the years 1993, 1994, 1995, 1996, 1997, 1998 and 1999 are 60, 90,, 120, 90, 60, 80 and 100 respectively.

Average annual exports (in Pesetas) of Company Y during the given period

= 1/7 x (80 + 40 + 60 + 60 + 80 + 100 + 140) = 560/7= 80.

Average annual exports (in Pesetas) of Company Z during the given period

= 1/7 x (60 + 90 + 120 + 90 + 60 + 80 + 100) = (600/7 ) .

Therefore Required percentage =

In which year was the difference between the exports from Companies X and Y the minimum?

### Answer & Explanation:

Answer: Option C

Explanation:

The difference between the exports from the Companies X and Y during the various years are:

In 1993 = (80 - 30) = 50

In 1994 = (60 - 40) = 20

In 1995 = (60 - 40) = 20

In 1996 = (70 - 60) = 10

In 1997 = (100 - 80) = 20

In 1998 = (100 - 50) = 50

In 1999 = (140 - 120) = 20

Clearly, the difference is minimum in the year 1996.

What was the difference between the average exports of the three Companies in 1993 and the average exports in 1998?

### Answer & Explanation:

Answer: Option C

Explanation:

Average exports of the three Companies X, Y and Z in 1993

= [ 1/3 x (30 + 80 + 60) ] = ( 170/3)

Average exports of the three Companies X, Y and Z in 1998

= [1/3 x (50 + 100 + 80) ] = (230/3)

Difference [ ( 230/3) - ( 170/3) ]

= ( 60/3) = 20

In how many of the given years, were the exports from Company Z more than the average annual exports over the given years?

### Answer & Explanation:

Answer: Option C

Explanation:

Average annual exports of Company Z during the given period

= 1/7 x (60 + 90 + 120 + 90 + 60 + 80 + 100)

= ( 600/7) = 85.71

From the analysis of graph the exports of Company Z are more than the average annual exports of Company Z (i.e., 85.71) during the years 1994, 1995, 1996 and 1999, i.e., during 4 of the given years.

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