# Line Charts Questions and Answers Home > Diagrammatic Tests > Data Interpretation > Line Charts >Line Chart Questions  The difference between the percentage of candidates qualified to appeared was maximum in which of the following pairs of years?

A. 1994 and 1995
B. 1997 and 1998
C. 1998 and 1999
D. 1999 and 2000

### Answer & Explanation:

Explanation:

The differences between the percentages of candidates qualified to appeared for the give pairs of years are:

For 1994 and 1995 = 50 - 30 = 20.

For 1998 and 1999 = 80 - 80 = 0.

For 1994 and 1997 = 50 - 30 = 20.

For 1997 and 1998 = 80 - 50 = 30.

For 1999 and 2000 = 80 - 60 = 20.

Thus, the maximum difference is between the years 1997 and 1998. In which pair of years was the number of candidates qualified, the same?

A. 1995 and 1997
B. 1995 and 2000
C. 1998 and 1999

### Answer & Explanation:

Explanation:

The graph gives the data for the percentage of candidates qualified to appeared and unless the absolute values of number of candidates qualified or candidates appeared is know we cannot compare the absolute values for any two years.

Hence, the data is inadequate to solve this question.  If the number of candidates qualified in 1998 was 21200, what was the number of candidates appeared in 1998?

A. 32000
B. 28500
C. 26500
D. 25000

### Answer & Explanation:

Explanation:

The number of candidates appeared in 1998 be x.

Then, 80% of x = 21200 => x = (21200x100)/80= 26500 (required number). If the total number of candidates appeared in 1996 and 1997 together was 47400, then the total number of candidates qualified in these two years together was?

A. 34700
B. 32100
C. 31500

### Answer & Explanation:

Explanation:

The total number of candidates qualified in 1996 and 1997 together, cannot be determined until we know at least, the number of candidates appeared in any one of the two years 1996 or 1997 or the percentage of candidates qualified to appeared in 1996 and 1997 together.

Hence, the data is inadequate. The total number of candidates qualified in 1999 and 2000 together was 33500 and the number of candidates appeared in 1999 was 26500. What was the number of candidates in 2000?

A. 24500
B. 22000
C. 20500
D. 19000

### Answer & Explanation:

Explanation:

The number of candidates qualified in 1999 = (80% of 26500) = 21200.

Therefore Number of candidates qualified in 2000 = (33500 - 21200) = 12300.

Let the number of candidates appeared in 2000 be x.

Then, 60% of x = 12300 => x = (12300x100)/60 = 20500.  #### Line Charts

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